Solar sizing gets split across a dozen articles that each answer one piece, and the pieces are easy to connect wrongly. This is the whole sequence in order: consumption, array, inverter, battery. Four steps, four formulas, one worked example carried through all of them.


Step 1: annual and daily kWh
Daily kWh = annual kWh ÷ 365
Pull twelve months of kWh from your utility account and add them. Twelve, not one — summer and winter can differ by 3x, and a single bill will mislead you in whichever direction it happens to sit. Our guide to calculating daily kWh usage covers the fallbacks if you cannot get a full year.
Worked example: 10,800 kWh a year ÷ 365 = 29.6 kWh per day.
Step 2: array size and panel count
System kW = annual kWh ÷ (peak sun hours × 365 × 0.8)
Panels = system watts ÷ panel watts
Peak sun hours is not daylight hours — it is roughly 3.2 in the Pacific Northwest and 6.0 in the Southwest. The 0.8 covers inverter, wiring, temperature and soiling losses; omitting it is the most common sizing error.
Worked example, at 4.5 peak sun hours: 10,800 ÷ (4.5 × 365 × 0.8) = 8.2 kW. At 400W per panel, that is 21 panels. The regional breakdown is in how many solar panels do I need to run my house.
Step 3: inverter rating
This is the step most sizing guides skip, and it is a different calculation from the array — the array is sized by energy, the inverter by power.
For a grid-tied system, the inverter is sized to the array with a DC-to-AC ratio of roughly 1.2, so an 8.2 kW array pairs with a 6.5-7 kW inverter. Clipping the rare peak is deliberate and costs very little energy.
For an off-grid or backup system, the inverter must instead cover your largest simultaneous load plus the surge of whatever motor starts under it — a well pump running at 1,000W can spike to 3,000W. Size this from an appliance list, not from the array. Our free wattage calculator returns both running and surge figures for exactly this.
There is one more ceiling to check: on a 200A service, interconnection rules usually cap backfed inverter output near 7.6 kW regardless of your array. See solar panel sizing for a 200 amp service before finalising.
Step 4: battery capacity
Usable kWh = critical daily kWh × days of autonomy
Two traps here. First, size against critical loads, not total consumption — a house averaging 29.6 kWh a day typically needs 4-8 kWh a day during an outage, and sizing to the full figure overbuilds by four times on the most expensive component. Second, usable is not nominal: LiFePO4 gives you 90-95% of its rating, lead-acid only 50%.
Worked example: 6 kWh of critical load × 2 days = 12 kWh usable. In LiFePO4 at 95% depth of discharge, that is about 12.6 kWh nominal. In lead-acid it would be 24 kWh nominal for the same result.
For a full three-day build including the winter-weather case, see solar and battery sizing for a 72-hour outage.
The whole example in one place
| Step | Formula | Result |
|---|---|---|
| 1. Consumption | 10,800 ÷ 365 | 29.6 kWh/day |
| 2. Array | 10,800 ÷ (4.5 × 365 × 0.8) | 8.2 kW — 21 × 400W panels |
| 3. Inverter | 8.2 ÷ 1.2, capped by service | 6.8 kW AC |
| 4. Battery | 6 kWh critical × 2 days ÷ 0.95 | 12.6 kWh nominal |
Sanity-check before you buy
- Does the array fit? 21 panels at ~21 sq ft each is about 440 sq ft of unshaded, well-oriented roof
- Does the inverter fit your service panel's backfeed limit?
- Is your export rate good enough to justify sizing to 100% of consumption, or is a smaller array plus storage the better return?
- Have you sized the inverter against surge watts, not just running watts?
- Are any large loads about to change — an EV, a heat pump, a pool?
Every number above is a planning estimate. Confirm final equipment sizing against a load calculation performed by a licensed electrician before ordering, particularly on the inverter and service-panel side.

